Test - TCAP Success Algebra 1 EOC Chapter 15

1 pt DOK: 2

What is the solution to the absolute value inequality $|3 (5 x + 8)| < 42$ ?

$x < - \frac{22}{5} or x > \frac{6}{5}$

$- \frac{22}{5} < x < \frac{6}{5}$

$x < \frac{6}{5} or x > \frac{22}{5}$

$\frac{6}{5} < x < \frac{22}{5}$

1 pt DOK: 3

Which of the following absolute value inequalities has the solution $- 14 \leq x \leq 10$ ?

$- 6 |x - 2| \leq - 72$

$- 6 |x - 2| \geq - 72$

$- 6 |x + 2| \leq - 72$

$- 6 |x + 2| \geq - 72$

1 pt DOK: 2

Solve: $39 + |10 x - 8| > 41$

$x = 1$

$x > 1 or x < \frac{3}{5}$

$x > \frac{3}{5}$

$x > 1 or x < - 1$

1 pt DOK: 2

Solve: $4 |7 x - 6| \geq 60$

$x \leq - \frac{9}{7}$

$x \leq - \frac{9}{7} or x \geq 3$

$x \leq 3$

$- \frac{9}{7} \leq x \leq 3$

1 pt DOK: 2

Solve: $|6 (3 x + 1)| = 42$

$x = - \frac{8}{3} or x = 2$

$x = \frac{8}{3} or x = - 2$

$x = 2$

$x = - \frac{8}{3}$

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