North Carolina Math 1 EOC - Practice Calculator Active

Terms are separated by multiplication and division signs; factors are separated by addition and subtraction signs.

Terms tell how many times to add a number to itself; factors tell how many times to multiply a number by itself.

Terms are separated by addition and subtraction signs; factors are separated by multiplication and division operators.

Terms are separated by addition and multiplication signs; factors are separated by subtraction and division signs.

$$x=10P(x)–8.95$$

$$x=–0.1P(x)+8.95$$

$$x=0.1P(x)–8.95$$

$$x=10P(x)–895$$

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by 1.023 for each year that $$x$$ that passes. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000{(1.023)}^{17}\approx 139,833$$.

The initial population was 95,000. It is given that the population declines each year by 2.3%, so we need to multiply 95,000 by 0.023 for each year that $$x$$ that passes. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000{(0.023)}^{17}\approx 0$$.

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by 0.023 for each year that $$x$$ that passes. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000{(0.023)}^{17}\approx 149,705$$.

The initial population was 95,000. It is given that the population grows each year by 2.3%, so we need to multiply 95,000 by $$(1+{2.3}^x)$$ for each year that $$x$$ that passes. The 1 is necessary part of the calculation because it accounts for the presence of the initial population, and adds growth per year, giving the current population. The population in 2020 can be found by substituting 17 in for $$x$$. Recall that $$x=0$$ indicated year 2003. So, $$P(17)=95,000(1+{2.3}^x)\approx 130$$ billion.

$$60{\text{ units}}^2$$

$$60\text{ units}$$

$$30{\text{ units}}^2$$

$$30\text{ units}$$

All of the above.